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X^2-300X-17600=0
a = 1; b = -300; c = -17600;
Δ = b2-4ac
Δ = -3002-4·1·(-17600)
Δ = 160400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{160400}=\sqrt{400*401}=\sqrt{400}*\sqrt{401}=20\sqrt{401}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-20\sqrt{401}}{2*1}=\frac{300-20\sqrt{401}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+20\sqrt{401}}{2*1}=\frac{300+20\sqrt{401}}{2} $
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